3.15.14 \(\int \frac {1}{x^{13} (2+x^6)^{3/2}} \, dx\) [1414]

Optimal. Leaf size=71 \[ \frac {5}{64 \sqrt {2+x^6}}-\frac {1}{24 x^{12} \sqrt {2+x^6}}+\frac {5}{96 x^6 \sqrt {2+x^6}}-\frac {5 \tanh ^{-1}\left (\frac {\sqrt {2+x^6}}{\sqrt {2}}\right )}{64 \sqrt {2}} \]

[Out]

-5/128*arctanh(1/2*(x^6+2)^(1/2)*2^(1/2))*2^(1/2)+5/64/(x^6+2)^(1/2)-1/24/x^12/(x^6+2)^(1/2)+5/96/x^6/(x^6+2)^
(1/2)

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Rubi [A]
time = 0.02, antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.385, Rules used = {272, 44, 53, 65, 213} \begin {gather*} \frac {5}{96 x^6 \sqrt {x^6+2}}+\frac {5}{64 \sqrt {x^6+2}}-\frac {5 \tanh ^{-1}\left (\frac {\sqrt {x^6+2}}{\sqrt {2}}\right )}{64 \sqrt {2}}-\frac {1}{24 x^{12} \sqrt {x^6+2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/(x^13*(2 + x^6)^(3/2)),x]

[Out]

5/(64*Sqrt[2 + x^6]) - 1/(24*x^12*Sqrt[2 + x^6]) + 5/(96*x^6*Sqrt[2 + x^6]) - (5*ArcTanh[Sqrt[2 + x^6]/Sqrt[2]
])/(64*Sqrt[2])

Rule 44

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n + 1
)/((b*c - a*d)*(m + 1))), x] - Dist[d*((m + n + 2)/((b*c - a*d)*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && ILtQ[m, -1] &&  !IntegerQ[n] && LtQ[n, 0]

Rule 53

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> Simp[(a + b*x)^(m + 1)*((c + d*x)^(n + 1
)/((b*c - a*d)*(m + 1))), x] - Dist[d*((m + n + 2)/((b*c - a*d)*(m + 1))), Int[(a + b*x)^(m + 1)*(c + d*x)^n,
x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && LtQ[m, -1] &&  !(LtQ[n, -1] && (EqQ[a, 0] || (NeQ[
c, 0] && LtQ[m - n, 0] && IntegerQ[n]))) && IntLinearQ[a, b, c, d, m, n, x]

Rule 65

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - a*(d/b) + d*(x^p/b))^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 213

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[b, 2])^(-1))*ArcTanh[Rt[b, 2]*(x/Rt[-a, 2])]
, x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 272

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[1/n, Subst[Int[x^(Simplify[(m + 1)/n] - 1)*(a
+ b*x)^p, x], x, x^n], x] /; FreeQ[{a, b, m, n, p}, x] && IntegerQ[Simplify[(m + 1)/n]]

Rubi steps

\begin {align*} \int \frac {1}{x^{13} \left (2+x^6\right )^{3/2}} \, dx &=\frac {1}{6} \text {Subst}\left (\int \frac {1}{x^3 (2+x)^{3/2}} \, dx,x,x^6\right )\\ &=\frac {1}{6 x^{12} \sqrt {2+x^6}}+\frac {5}{12} \text {Subst}\left (\int \frac {1}{x^3 \sqrt {2+x}} \, dx,x,x^6\right )\\ &=\frac {1}{6 x^{12} \sqrt {2+x^6}}-\frac {5 \sqrt {2+x^6}}{48 x^{12}}-\frac {5}{32} \text {Subst}\left (\int \frac {1}{x^2 \sqrt {2+x}} \, dx,x,x^6\right )\\ &=\frac {1}{6 x^{12} \sqrt {2+x^6}}-\frac {5 \sqrt {2+x^6}}{48 x^{12}}+\frac {5 \sqrt {2+x^6}}{64 x^6}+\frac {5}{128} \text {Subst}\left (\int \frac {1}{x \sqrt {2+x}} \, dx,x,x^6\right )\\ &=\frac {1}{6 x^{12} \sqrt {2+x^6}}-\frac {5 \sqrt {2+x^6}}{48 x^{12}}+\frac {5 \sqrt {2+x^6}}{64 x^6}+\frac {5}{64} \text {Subst}\left (\int \frac {1}{-2+x^2} \, dx,x,\sqrt {2+x^6}\right )\\ &=\frac {1}{6 x^{12} \sqrt {2+x^6}}-\frac {5 \sqrt {2+x^6}}{48 x^{12}}+\frac {5 \sqrt {2+x^6}}{64 x^6}-\frac {5 \tanh ^{-1}\left (\frac {\sqrt {2+x^6}}{\sqrt {2}}\right )}{64 \sqrt {2}}\\ \end {align*}

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Mathematica [A]
time = 0.10, size = 54, normalized size = 0.76 \begin {gather*} \frac {-8+10 x^6+15 x^{12}}{192 x^{12} \sqrt {2+x^6}}-\frac {5 \tanh ^{-1}\left (\frac {\sqrt {2+x^6}}{\sqrt {2}}\right )}{64 \sqrt {2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/(x^13*(2 + x^6)^(3/2)),x]

[Out]

(-8 + 10*x^6 + 15*x^12)/(192*x^12*Sqrt[2 + x^6]) - (5*ArcTanh[Sqrt[2 + x^6]/Sqrt[2]])/(64*Sqrt[2])

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Maple [A]
time = 0.38, size = 51, normalized size = 0.72

method	result	size
risch	\(\frac {15 x^{12}+10 x^{6}-8}{192 x^{12} \sqrt {x^{6}+2}}+\frac {5 \sqrt {2}\, \ln \left (\frac {\sqrt {x^{6}+2}-\sqrt {2}}{\sqrt {x^{6}}}\right )}{128}\)	\(51\)
trager	\(\frac {15 x^{12}+10 x^{6}-8}{192 x^{12} \sqrt {x^{6}+2}}+\frac {5 \RootOf \left (\textit {\_Z}^{2}-2\right ) \ln \left (\frac {-\RootOf \left (\textit {\_Z}^{2}-2\right )+\sqrt {x^{6}+2}}{x^{3}}\right )}{128}\)	\(55\)
meijerg	\(\frac {\sqrt {2}\, \left (\frac {\sqrt {\pi }\, \left (-\frac {47}{4} x^{12}-12 x^{6}+8\right )}{8 x^{12}}-\frac {\sqrt {\pi }\, \left (-15 x^{12}-10 x^{6}+8\right )}{8 x^{12} \sqrt {1+\frac {x^{6}}{2}}}-\frac {15 \sqrt {\pi }\, \ln \left (\frac {1}{2}+\frac {\sqrt {1+\frac {x^{6}}{2}}}{2}\right )}{8}+\frac {15 \left (\frac {47}{30}-3 \ln \left (2\right )+6 \ln \left (x \right )\right ) \sqrt {\pi }}{16}-\frac {\sqrt {\pi }}{x^{12}}+\frac {3 \sqrt {\pi }}{2 x^{6}}\right )}{48 \sqrt {\pi }}\)	\(109\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^13/(x^6+2)^(3/2),x,method=_RETURNVERBOSE)

[Out]

1/192*(15*x^12+10*x^6-8)/x^12/(x^6+2)^(1/2)+5/128*2^(1/2)*ln(((x^6+2)^(1/2)-2^(1/2))/(x^6)^(1/2))

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Maxima [A]
time = 0.51, size = 81, normalized size = 1.14 \begin {gather*} \frac {5}{256} \, \sqrt {2} \log \left (-\frac {\sqrt {2} - \sqrt {x^{6} + 2}}{\sqrt {2} + \sqrt {x^{6} + 2}}\right ) - \frac {50 \, x^{6} - 15 \, {\left (x^{6} + 2\right )}^{2} + 68}{192 \, {\left ({\left (x^{6} + 2\right )}^{\frac {5}{2}} - 4 \, {\left (x^{6} + 2\right )}^{\frac {3}{2}} + 4 \, \sqrt {x^{6} + 2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^13/(x^6+2)^(3/2),x, algorithm="maxima")

[Out]

5/256*sqrt(2)*log(-(sqrt(2) - sqrt(x^6 + 2))/(sqrt(2) + sqrt(x^6 + 2))) - 1/192*(50*x^6 - 15*(x^6 + 2)^2 + 68)
/((x^6 + 2)^(5/2) - 4*(x^6 + 2)^(3/2) + 4*sqrt(x^6 + 2))

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Fricas [A]
time = 0.34, size = 71, normalized size = 1.00 \begin {gather*} \frac {15 \, \sqrt {2} {\left (x^{18} + 2 \, x^{12}\right )} \log \left (\frac {x^{6} - 2 \, \sqrt {2} \sqrt {x^{6} + 2} + 4}{x^{6}}\right ) + 4 \, {\left (15 \, x^{12} + 10 \, x^{6} - 8\right )} \sqrt {x^{6} + 2}}{768 \, {\left (x^{18} + 2 \, x^{12}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^13/(x^6+2)^(3/2),x, algorithm="fricas")

[Out]

1/768*(15*sqrt(2)*(x^18 + 2*x^12)*log((x^6 - 2*sqrt(2)*sqrt(x^6 + 2) + 4)/x^6) + 4*(15*x^12 + 10*x^6 - 8)*sqrt
(x^6 + 2))/(x^18 + 2*x^12)

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Sympy [A]
time = 3.70, size = 68, normalized size = 0.96 \begin {gather*} - \frac {5 \sqrt {2} \operatorname {asinh}{\left (\frac {\sqrt {2}}{x^{3}} \right )}}{128} + \frac {5}{64 x^{3} \sqrt {1 + \frac {2}{x^{6}}}} + \frac {5}{96 x^{9} \sqrt {1 + \frac {2}{x^{6}}}} - \frac {1}{24 x^{15} \sqrt {1 + \frac {2}{x^{6}}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**13/(x**6+2)**(3/2),x)

[Out]

-5*sqrt(2)*asinh(sqrt(2)/x**3)/128 + 5/(64*x**3*sqrt(1 + 2/x**6)) + 5/(96*x**9*sqrt(1 + 2/x**6)) - 1/(24*x**15
*sqrt(1 + 2/x**6))

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Giac [A]
time = 1.41, size = 68, normalized size = 0.96 \begin {gather*} \frac {5}{256} \, \sqrt {2} \log \left (-\frac {\sqrt {2} - \sqrt {x^{6} + 2}}{\sqrt {2} + \sqrt {x^{6} + 2}}\right ) + \frac {1}{24 \, \sqrt {x^{6} + 2}} + \frac {7 \, {\left (x^{6} + 2\right )}^{\frac {3}{2}} - 18 \, \sqrt {x^{6} + 2}}{192 \, x^{12}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^13/(x^6+2)^(3/2),x, algorithm="giac")

[Out]

5/256*sqrt(2)*log(-(sqrt(2) - sqrt(x^6 + 2))/(sqrt(2) + sqrt(x^6 + 2))) + 1/24/sqrt(x^6 + 2) + 1/192*(7*(x^6 +
2)^(3/2) - 18*sqrt(x^6 + 2))/x^12

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Mupad [B]
time = 1.53, size = 65, normalized size = 0.92 \begin {gather*} -\frac {\frac {25\,x^6}{96}-\frac {5\,{\left (x^6+2\right )}^2}{64}+\frac {17}{48}}{4\,\sqrt {x^6+2}-4\,{\left (x^6+2\right )}^{3/2}+{\left (x^6+2\right )}^{5/2}}-\frac {5\,\sqrt {2}\,\mathrm {atanh}\left (\frac {\sqrt {2}\,\sqrt {x^6+2}}{2}\right )}{128} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^13*(x^6 + 2)^(3/2)),x)

[Out]

- ((25*x^6)/96 - (5*(x^6 + 2)^2)/64 + 17/48)/(4*(x^6 + 2)^(1/2) - 4*(x^6 + 2)^(3/2) + (x^6 + 2)^(5/2)) - (5*2^
(1/2)*atanh((2^(1/2)*(x^6 + 2)^(1/2))/2))/128

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